The current sensitivity of a galvanometer which is used as an ammeter is doubled by doubling the number of turns in the coil . then , the voltage sensitivity of the galvanometer if it is used as voltmeter in the same way would :

be doubled 

$\text {Current Sensitivity of a galvanometer is } = NBAK$

$\text {Voltage Sensitivity of a galvanometer is } = \frac{NBAK}{R} $

$\Rightarrow \text{Voltage Sensitivity of a galvanometer be doubled}$