Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Laws of Motion

Question:

Block B has mass m and is released from rest when it is on top of wedge A, which has a mass 3 m. Determine the tension in cord CD needed to hold the wedge from moving while B is sliding down A. Neglect friction :

980871

Options:

2 mg cos θ

mg/2 cos θ

mg/2 sin 2θ

mg sin 2θ

Correct Answer:

mg/2 sin 2θ

Explanation:

\(T = N \sin {\theta} \text{ and} N = mg \cos {\theta}\)

\(T = mg \cos {\theta} \sin {\theta}\)

\(T = \frac{mg}{2} \sin {2\theta}\)