A boy reduces his speed to \(\frac{7}{11}\) and reaches his destination in 22 hours. How much time he will save if he walk at his initial speed?
Answer & explanation
Correct answer: option 4
S1 = Actual Speed
S2 = New Speed
T1 = Actual Time
T2 = New Time
*Time ∝ Speed when distance is same*
ATQ,
S1 : S2 = 11 : 7
T1 : T2 = 7 : 11 ⇒ 4R (Saved time at normal speed)
11R = 22hrs (given)
1R = 2hrs.
Time save at normal speed = 4R = 4× 2 = 8 hrs.