Two places A and B are 506 km apart. Train X leaves from A to B and Train Y leaves from B to A at the same time. Both trains meet after 5\(\frac{1}{2}\) hour. The speed of Y is 10 km/h more than X. What is the speed of X (in km/h)?
Answer & explanation
Correct answer: option 1
Let speed of X = X and Y = Y
X + Y = \(\frac{506}{11}\) × 2 = 46 × 2 = 92
X + Y = 92 .......(i)
and Y - X = 10 (given).....(ii)
Now,
(i) + (ii)
⇒ 2Y = 102
⇒ Y = 51
from (ii), if Y = 51, then
⇒ X = 41