A tour operator charges ₹136 per passenger for 100 passengers with a discount of ₹4 for each 10 passengers in excess of 100. Find the number of passengers that will maximise the amount of money the tour operator receives.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 220
Let the number of passengers that are in excess of 100 be 10x, then amount received by the tour operator is
$A = (100+ 10x) (136 - 4x)$
$⇒A = 13600-400x + 1360x-40x^2$
$⇒A = 13600 + 960x - 40x^2$
Diff. w.r.t. x, we get
$\frac{dA}{dx}=0+960-80x$
and $\frac{d^2A}{dx^2}= -80$.
Now, $\frac{dA}{dx}=0⇒960-80x = 0⇒x= 12$.
Also, $\left[\frac{d^2A}{dx^2}\right]_{x=12}=-80<0$
⇒ A is maximum at $x = 12$.
Hence, the number of passengers for which the tour operator received maximum amount is $100 + 10 × 12$ i.e. 220.