If a line makes angles $α,β$ and $γ$ with the positive directions of coordinate axes respectively, then $\cos 2α + \cos 2β + \cos 2γ$ is equal to |
1 -1 2 -2 |
-1 |
The correct answer is Option (2) → -1 Use the identity: $\cos 2\alpha = 2\cos^{2}\alpha - 1$ So, $\cos 2\alpha + \cos 2\beta + \cos 2\gamma$ $= 2(\cos^{2}\alpha + \cos^{2}\beta + \cos^{2}\gamma) - 3$ For a line in 3-D, direction cosines satisfy: $\cos^{2}\alpha + \cos^{2}\beta + \cos^{2}\gamma = 1$ Therefore, $\cos 2\alpha + \cos 2\beta + \cos 2\gamma = 2(1) - 3 = -1$ The value is $-1$. |