CUET Preparation Today
If y =cos x then for what value of x we have \(\frac{d^2 y}{dx^2}\) = 0? |
0 \[\frac{\pi }{6}\] \[\frac{\pi }{4}\] \[\frac{\pi }{2}\] |
\[\frac{\pi }{2}\] |
\(\frac{d^2 y}{dx^2}\) = -cos x ehich will be 0 only when x = \(\frac{\pi }{2}\) |
