If y =cos x then for what value of x we have \(\frac{d^2 y}{dx^2}\) = 0?
Answer & explanation
Correct answer: option 4
\(\frac{d^2 y}{dx^2}\) = -cos x ehich will be 0 only when x = \(\frac{\pi }{2}\)
If y =cos x then for what value of x we have \(\frac{d^2 y}{dx^2}\) = 0?
Correct answer: option 4
\(\frac{d^2 y}{dx^2}\) = -cos x ehich will be 0 only when x = \(\frac{\pi }{2}\)