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A transistor having $β$ equal to 80 has a change in base current of 250 μA, then the change in collector current is - |
(250 – 80)μA (250 + 80)μA $\frac{250}{80}μA$ 80 × 250 μA |
80 × 250 μA |
Using $β=\frac{I_c}{I_b}$ we get $⇒I_c=I_b×β=250×80μA $ |
