A transistor having $β$ equal to 80 has a change in base current of 250 μA, then the change in collector current is -

(250 – 80)μA (250 + 80)μA $\frac{250}{80}μA$ 80 × 250 μA

80 × 250 μA

Using $β=\frac{I_c}{I_b}$ we get $⇒I_c=I_b×β=250×80μA $