Practicing Success
Seven resistors, each of 1Ω resistance are connected as shown in figure. What is the effective resistance between A and B ? |
$\frac{4}{7}$ Ω 7 Ω $\frac{8}{7}$ Ω $\frac{3}{2}$ Ω |
$\frac{8}{7}$ Ω |
Let a cell of emf ε be connected between A and B. The currents through the various arms will be as shown in the figure. Applying Kirchhoff’s loop law in closed loop ACEA, we get $-I_1-I_2+\left(I-I_1\right)=0$ $I=2 I_1+I_2$ (i) Again applying Kirchhoff's loop law in closed CEDC, we get $-I_2-I_2+\left(I_1-I_2\right)=0$ or $3 I_2=I_1$ Putting this value in (i), we get $I=2 I_1+\frac{I_1}{3}$ or $I_1=\left(\frac{3}{7}\right) I$ Again applying Kirchhoff's loop law in closed loop AEBA, we get $-\left(I-I_1\right)-\left(I-I_1\right)+\varepsilon=0$ $\varepsilon=2\left(I-I_1\right)$ $\varepsilon=2\left(I-\frac{3 I}{7}\right)=\frac{8 I}{7}$ If R is the effective resistance between A and B, then ε = IR So IR = $\frac{8 I}{7}$ or $R=\frac{8}{7} \Omega$ |