Electric potential due to dielectric dipole on equatonal line at distance r from the centre of the dipole is (P = dipole moment) (assume dipole as very short). |
\(V=\pm \frac{1}{4 \pi \varepsilon_0} \frac{P}{r^2} \) \(V=\pm \frac{1}{4 \pi \varepsilon_0} \frac{2 P}{r^2} \) \(V = \pm \frac{1}{4 \pi \varepsilon_0} \frac{P}{r^3} \) V = 0 |
V = 0 |
The correct answer is Option (4) → V = 0 As potential due to two charges {q and -q} cancel each other at the distance mid-point. ∴ V = 0 |