The value of $\frac{cos^289°+cos^21°}{cos30°sin90°-sin30°cos90°}$ is :
Answer & explanation
Correct answer: option 1
Using ,
cos θ = sin ( 90º - θ )
Now,
$\frac{cos^289°+cos^21°}{cos30°sin90°-sin30°cos90°}$
= $\frac{cos^289°+sin^289°}{√3/2 × 1 - 1/2 × 0}$
using ,
sin²θ + cos²θ = 1
= $\frac{1}{√3/2}$
= $\frac{2}{√3}$