Piyush and Kesari start at the same time to travel from place P to Q, which is 100 kms apart . Piyush travels 5 km/h slower than Kesari . Kesari reaches place Q and at once turns back meeting Piyush, 20 kms from place Q . Kesari's speed (in km/h) is ?
Answer & explanation
Correct answer: option 2
Let speed of Piyush = S
Speed of Kesari = S + 5
Distance travelled by Kesari = (100 + 20) = 120
Distance travelled by Piyush = (100 - 20) = 80
As per question,
\(\frac{120}{S + 5}\) = \(\frac{80}{S}\)
120 S = 80 S + 80 × 5
40 S = 80 × 5
S = 10 km/h
Speed of Kesari = S + 5 = 10 + 5 = 15 km/hr