Practicing Success
What is the value of [(cos 5A + cos 3A)] ÷ [( sin 5A - sin 3A)] ? |
tan A sec A . tan A cot A cosec2 A - cot2 A |
cot A |
Here, (cos A + cos B = 2 cos (\(\frac{A+B}{2}\)) cos (\(\frac{A-B}{2}\)) and (sin A - sin B = 2 cos (\(\frac{A+B}{2}\)) sin (\(\frac{A-B}{2}\)) Here using these formulas: ⇒ \(\frac{cos 5A + cos 3A}{(sin 5A + sin 3A)}\) = \(\frac{2cos\;\frac{(5A\;+\;3A)}{2}\;cos\;\frac{(5A\;-\;3A)}{2}}{2cos\;\frac{(5A\;+\;3A)}{2}\;sin\;\frac{(5A\;-\;3A)}{2}}\) = \(\frac{2cos4A\;cosA}{2cos 4A\;sinA}\) = cot A |