Suresh covers a distance by a cycle at 10 km/h. He returns to the starting point in a car at a speed of 50 km/h. Find the average speed for the entire journey.

36.66 km/h 16.66 km/h 26.66 km/h 46.66 km/h

16.66 km/h

When distance is equal, then Average speed = \(\frac{2(S1\;×\;S2)}{S1\;+\;S2}\) Where, S1 = 1st speed and S2 = 2nd speed ATQ, Average speed = \(\frac{2(10\;×\;50)}{10\;+\;50}\) = \(\frac{100}{6}\) = 16.66 km/h