Practicing Success
If the function f(x) = cos |x| -2ax + b increases for all x ∈ R, then |
a ≤ b $a=\frac{b}{2}$ $a≤-\frac{1}{2}$ $a≥-\frac{3}{2}$ |
$a≤-\frac{1}{2}$ |
Here $f'(x) ≥ 0, ∀x ∈ R$ $⇒ -sinx - 2a ≥ 0, ∀x ∈ R$ $⇒ a ≤ -\frac{sinx}{2} ⇒ a ≤ -\frac{1}{2}$. Hence (C) is the correct answer. |