Find θ, if cos θ = -(√3)/2.

cos θ = $-\frac{\sqrt{3}}{2}$

{ we know, cos 30 º= $\frac{\sqrt{3}}{2}$ }

30º= \(\frac{π}{6}\)

cos is negative that means it lies in 2nd quadrant .

So,  θ = π - \(\frac{π}{6}\)

= \(\frac{5π}{6}\)