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If 2sinA + cosecA = 2\(\sqrt {2}\), 0° < θ < 90° than find the value of 2(sin4A + cos4A) |
2 1 4 0 |
1 |
Put θ = 45° (satisfying the given equation) 2sinA + cosecA = 2\(\sqrt {2}\) \(\frac{2}{\sqrt {2}}\) + \(\sqrt {2}\) = 2\(\sqrt {2}\) satisfied ⇒ 2((\(\frac{1}{\sqrt {2}}\))4+(\(\frac{1}{\sqrt {2}}\))4) = 2(\(\frac{1}{4}\)+\(\frac{1}{4}\)) = 1 |
