If 2sinA + cosecA = 2\(\sqrt {2}\), 0° < θ < 90°
than find the value of 2(sin4A + cos4A)
Answer & explanation
Correct answer: option 2
Put θ = 45° (satisfying the given equation)
2sinA + cosecA = 2\(\sqrt {2}\)
\(\frac{2}{\sqrt {2}}\) + \(\sqrt {2}\) = 2\(\sqrt {2}\) satisfied
⇒ 2((\(\frac{1}{\sqrt {2}}\))4+(\(\frac{1}{\sqrt {2}}\))4)
= 2(\(\frac{1}{4}\)+\(\frac{1}{4}\))
= 1