What will be the voltage drop across an inductor of inductance L carrying current I ?
Answer & explanation
Correct answer: option 3
The expression for voltage drop across an inductor : VL = L\(\frac{dI}{dt}\)
What will be the voltage drop across an inductor of inductance L carrying current I ?
Correct answer: option 3
The expression for voltage drop across an inductor : VL = L\(\frac{dI}{dt}\)