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What will be the voltage drop across an inductor of inductance L carrying current I ? |
L\(\frac{d^2I}{dt^2}\) \(\frac{dI}{dt}\) (1/L) L\(\frac{dI}{dt}\) \(\frac{d^2I}{dt^2}\) (1/L) |
L\(\frac{dI}{dt}\) |
The expression for voltage drop across an inductor : VL = L\(\frac{dI}{dt}\) |
