Practicing Success
Chlorobenzene can be prepared by reacting aniline with |
hydrochloric acid cuprous chloride chlorine in presence of anhydrous AlCl3 nitrous acid followed by heating with cuprous chloride |
nitrous acid followed by heating with cuprous chloride |
The correct answer is option 4. nitrous acid followed by heating with cuprous chloride. Aniline is a base which is an aromatic amine. The question says that aniline is reacted with a reagent and gives chlorobenzene. This means that the amine group of the aniline is to be replaced on reaction with the reagent with a chlorine atom. We know that amine group can only be replaced after it has been converted to diazonium salt form which is an unstable compound and direct halogenation of aniline gives halogen derivatives of aniline. When hydrochloric acid is added to aniline, the aniline being a base will abstract the proton forming anilinium chloride salt. Nitrous acid produced in situ by sodium nitrite and hydrochloric acid on reaction with aniline at low temperature (0∘C−5∘C) converts aniline to a benzene diazonium salt and this reaction is known as diazotization. When a freshly prepared solution of benzene diazonium salt is treated with cuprous oxide, chlorobenzene is obtained. This reaction is known as Sandmeyer’s reaction. Therefore, as the conclusion, we can say that chlorobenzene can be prepared by reacting aniline with nitrous acid followed by heating with cuprous chloride (CuCl). |