Practicing Success
If µ0 be the permeability and ε0 be the permittivity of a medium, then its refractive index is given by: |
$\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$ $\frac{1}{\mu_0 \varepsilon_0}$ $\sqrt{\mu_0 \varepsilon_0}$ $\mu_0 \varepsilon_0$ |
$\sqrt{\mu_0 \varepsilon_0}$ |
Refractive index of medium is $=\frac{c}{v}$ Where $c=\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$ and $v=\frac{1}{\sqrt{\mu_0 \varepsilon_0 \mu_{r} \varepsilon_{r}}}$ ∴ $\mu=\frac{1 / \sqrt{\mu_0 \varepsilon_0}}{1 / \sqrt{\mu_0 \varepsilon_0 \mu_{r} \varepsilon_{r}}}=\sqrt{\mu_{r} \varepsilon_{r}}$ Given, $\mu_{r}=\mu_0$ and $\varepsilon_{r}=\varepsilon_0$ then $\mu=\sqrt{\mu_0 \varepsilon_0}$ |