Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

E and V, respectively, denote electric field intensity and electrostatic potential at a point. The correct relation between the two is

Options:

$E=dV/dr$

$E=-dV/dr$

$V = dE/dr$

$V=-dE/dr$

Correct Answer:

$E=-dV/dr$

Explanation:

The correct answer is Option (2) → $E=-dV/dr$

The electric field $\vec{E}$ is related to the electrostatic potential $V$ by:

$\vec{E} = - \vec{\nabla} V$

In one dimension:

$E = - \frac{dV}{dx}$

The negative sign indicates that the electric field points in the direction of decreasing potential.