E and V, respectively, denote electric field intensity and electrostatic potential at a point. The correct relation between the two is |
$E=dV/dr$ $E=-dV/dr$ $V = dE/dr$ $V=-dE/dr$ |
$E=-dV/dr$ |
The correct answer is Option (2) → $E=-dV/dr$ The electric field $\vec{E}$ is related to the electrostatic potential $V$ by: $\vec{E} = - \vec{\nabla} V$ In one dimension: $E = - \frac{dV}{dx}$ The negative sign indicates that the electric field points in the direction of decreasing potential. |