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Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and other is decreased by 10%. The new force of repulsion at the same distance will be |
55N 77 N 99 N 100 N |
99 N |
$F = 100 = \frac{kq^2}{r}$ $F'= \frac{k(1.1q)(0.9q)}{r} = 0.99 \frac{kq^2}{r} = 99 N$ |
