Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

$F = 100 = \frac{kq^2}{r}$

$F'= \frac{k(1.1q)(0.9q)}{r} = 0.99 \frac{kq^2}{r} = 99 N$