Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The value of $cos^{-1}\left(cos (-680°)\right)$, is

Options:

$\frac{\pi}{9}$

$\frac{2\pi}{9}$

$\frac{4\pi}{9}$

$-\frac{\pi}{9}$

Correct Answer:

$\frac{2\pi}{9}$

Explanation:

$cos^{-1}\begin{Bmatrix}cos (-680°)\end{Bmatrix}=cos^{-1} (680°)$

$=cos^{-1}\begin{Bmatrix}cos\left(680×\frac{\pi}{180}\right)\end{Bmatrix}=cos^{-1}\left(cos\frac{34\pi}{9}\right)$

$=cos^{-1}\begin{Bmatrix}cos\left(4\pi -\frac{2\pi}{9}\right)\end{Bmatrix}=cos^{-1}\left(cos\frac{2\pi}{9}\right)=\frac{2\pi}{9}$