A satellite which is geo-stationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is
Answer & explanation
Correct answer: option 3
$\frac{\mathrm{T}_{2 \mathrm{nd}}^2}{\mathrm{~T}_{1 \mathrm{st}}^2}=\frac{(2 \mathrm{a})^3}{(\mathrm{a})^3}=2^3=8$
$\mathrm{~T}_{2 \mathrm{nd}}=\mathrm{T}_{1 \mathrm{st}} \times \sqrt{8}=24 \times 2 \sqrt{2}=48 \sqrt{2}$ hrs