Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

A satellite which is geo-stationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is

Options:

24 hrs

48 hrs

48$\sqrt{2}$ hrs

$\frac{48}{\sqrt{2}}$ hrs

Correct Answer:

48$\sqrt{2}$ hrs

Explanation:

$\frac{\mathrm{T}_{2 \mathrm{nd}}^2}{\mathrm{~T}_{1 \mathrm{st}}^2}=\frac{(2 \mathrm{a})^3}{(\mathrm{a})^3}=2^3=8$

$\mathrm{~T}_{2 \mathrm{nd}}=\mathrm{T}_{1 \mathrm{st}} \times \sqrt{8}=24 \times 2 \sqrt{2}=48 \sqrt{2}$ hrs