The value of $\int\limits_0^3|2 x-6| dx$ is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 9
$\int\limits_0^3|x-3|dx$
since from 0 → 3, x ⇒ 3
$⇒I=2\int\limits_0^33-xdx$
$=2\left[3x-\frac{x^2}{2}\right]_0^3$ ⇒ 9 units