What will be the value of cosx cosecx - sinx secx

cot\(\frac{2x}{2}\) sin\(\frac{x}{2}\) 2cot2x sec\(\frac{2x}{3}\)

2cot2x

cosx cosecx - sinx secx  = \(\frac{cosx}{sinx}\)-\(\frac{sinx}{cosx}\)    = \(\frac{(cos^2x-sin^2x)}{sinx cosx}\) Multiply and divide by 2 \(\frac{2(cos^2x-sin^2x)}{2(sinx cosx)}\) = \(\frac{2cos2x}{sin2x}\)          [cos2x= cos2x - sin2x, sin2x = 2sinx cosx] = 2cot2x