What will be the value of cosx cosecx - sinx secx

cosx cosecx - sinx secx 

= \(\frac{cosx}{sinx}\)-\(\frac{sinx}{cosx}\)   

= \(\frac{(cos^2x-sin^2x)}{sinx cosx}\)

Multiply and divide by 2

\(\frac{2(cos^2x-sin^2x)}{2(sinx cosx)}\) = \(\frac{2cos2x}{sin2x}\)          [cos2x= cos²x - sin²x, sin2x = 2sinx cosx]

= 2cot2x