If 4x2 + 3y2 = 67, xy = 4 (x,

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If 4x² + 3y² = 67, xy = 4 (x, y > 0)

find x³ + y².

Options:

Correct Answer:

Explanation:

By Putting x = 4 and y = 1

These values are satisfying the equations:

⇒ 4x² + 3y² = 67

⇒ 4(4)² + 3(1)² = 67

⇒ 67 = 67

Put these values and find:

⇒ x³ + y² = (4)³ + (1)²= 64 + 1 = 65