Practicing Success
Electrical work done in one second is equal to electrical potential multiplied by total charge passed. If we want to obtain maximum work from a galvanic cell then charge has to be passed reversibly. The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy and therefore, if the EMF of the cell is E and nF is the amount of charge passed and ∆rG is the Gibbs energy of the reaction, then ∆rG = – nFEcell It may be remembered that Ecell is an intensive parameter but ∆rG is an extensive thermodynamic property and the value depends on n. From the measurement of Eocell , we can obtain an important thermodynamic quantity, ∆rGo , standard Gibbs energy of the reaction. |
Which is the correct cell notation? |
Cu|Cu2+(0.2M)||Zn|Zn2+(0.1M) Zn|Zn2+(0.1M)||Cu2+(0.2M)|Cu Cu|Cu2+(0.1M)||Zn|Zn2+(0.2M) Zn|Zn2+(0.2M)||Cu|Cu2+(0.1M) |
Zn|Zn2+(0.1M)||Cu2+(0.2M)|Cu |
Zn|Zn2+(0.1M) || Cu2+(0.2M)|Cu Anode salt Cathode (-) bridge (+) |