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Focal length of a convex lens of refractive index 1.5 is 2 cm. Focal length of lens when immersed in a liquid of refractive index 1.25 will be |
5 cm 7.5 cm 10 cm 2.5 cm |
5 cm |
$\frac{f_p}{f_a}=\frac{\left(\mu_g-1\right)}{\left(\frac{\mu_g}{\mu_l}-1\right)} \Rightarrow f_l=\frac{5}{2} \times f_a$ $\frac{5}{2} \times 2$ cm = 5 cm |