A TV tower has a height of 100 m. How much population is covered by the TV broadcast if the average population density around the tower is 1000 km–2? (radius of the earth = $6.37 × 10^6 m$)
Answer & explanation
Correct answer: option 4
$d = \sqrt{2hR}$
Population covered
$=πd^2$ × population density
$=3.14 ×2hR ×1000× (10^{-3})^2$
$=3.14×2×100×6.37×10^6×1000×10^{−6}$
$= 40×10^5$ = 40lakhs