A TV tower has a height of 100 m. How much population is covered by the TV broadcast if the average population density around the tower is 1000 km–2? (radius of the earth = $6.37 × 10^6 m$)

4 lakh 4 billion 40,000 40 lakh

40 lakh

$d = \sqrt{2hR}$ Population covered $=πd^2$ × population density $=3.14 ×2hR ×1000× (10^{-3})^2$ $=3.14×2×100×6.37×10^6×1000×10^{−6}$ $= 40×10^5$ = 40lakhs