Practicing Success
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What is the value of $\frac{9x^2 + 12 xy +4y^2}{36}$ ? |
$(\frac{x}{3}+\frac{y}{2})^2$ $(\frac{x}{2}-\frac{y}{3})^2$ $(\frac{x}{2}+\frac{y}{3})^2$ $(\frac{x}{4}+\frac{y}{3})^2$ |
$(\frac{x}{2}+\frac{y}{3})^2$ |
$\frac{9x^2 + 12 xy +4y^2}{36}$ This equation can be written as = \(\frac{(3x + 2y)^2}{6^2}\) = $(\frac{x}{2}+\frac{y}{3})^2$
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