Find the HCF of $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$
Answer & explanation
Correct answer: option 1
HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are : $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$.
LCM of 25, 20, 15, 33 = 3300
HCF of 11, 9, 16, 10 = 1
The HCF of $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$ is = \(\frac{1}{3300}\)