Find the HCF of $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$

$\frac{1}{3300}$

HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)

The given fractions are :  $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$.

LCM of 25, 20, 15, 33 = 3300

HCF of 11, 9, 16, 10 = 1

The HCF of $\frac{11}{25},\frac{9}{20},\frac{16}{15}$ and $\frac{10}{33}$ is = \(\frac{1}{3300}\)