A point charge 17.7 μC is placed at a perpendicular distance of 5 cm from the centre of a square. The amount of electric flux going through the square will be

(given = $8.85×10^{-12}C^{-2}N^{-1}m^{-2}$)

$3. 33 × 10^5 N\, m^2/C$

The correct answer is Option (1) → $3. 33 × 10^5 N\, m^2/C$

Given:

$q = 17.7\ \mu C = 17.7 \times 10^{-6}\ C$

Square is one of six faces of an imaginary cube → flux through square = $\frac{1}{6}$ of total flux.

Total flux: $\Phi_{total} = \frac{q}{\varepsilon_0}$

Flux through square: $\Phi = \frac{q}{6\varepsilon_0}$

Substitute values:

$\Phi = \frac{17.7 \times 10^{-6}}{6 \times 8.854 \times 10^{-12}}$

$\Phi = \frac{17.7 \times 10^{-6}}{5.3124 \times 10^{-11}} = 3.33 \times 10^{5}\ \text{N·m}^2\text{/C}$

Electric flux through the square = $3.33 \times 10^{5}\ \text{N·m}^2\text{/C}$