Practicing Success
Pure Si at 500K has equal number of electron $(n_e)$ and hole $(n_h)$ concentrations of $1.5 × 10^{16} m^{–3}$. Doping by indium increases nh to $4.5 × 10^{22} m^{–3}$. The doped semiconductor is of |
n–type with electron concentration $n_e = 5 × 10^{22} m^{–3}$ p–type with electron concentration $n_e = 2.5 ×10^{10} m^{–3}$ n–type with electron concentration $n_e = 2.5 × 10^{23} m^{–3}$ p–type having electron concentration $n_e = 5 × 10^9 m^{–3}$ |
p–type having electron concentration $n_e = 5 × 10^9 m^{–3}$ |
$n_i^2= n_en_h$ $(1.5×10^{16})^2 = n_3(4.5×10^{22})$ $⇒ n_e = 0.5×10^{10}$ or $n_e = 5×10^9$ Given $n_h = 4.5×10^{22}$ $⇒ n_h = 4.5×10^{22}$ |