Practicing Success
$sin^{-1}\begin{Bmatrix}cos(sin^{-1}x)\end{Bmatrix}+cos^{-1}\begin{Bmatrix}sin(cos^{-1}x)\end{Bmatrix}$ is equal to |
$\frac{\pi}{4}$ $\frac{\pi}{2}$ $\frac{3\pi}{4}$ 0 |
$\frac{\pi}{2}$ |
We have, $sin^{-1}\begin{Bmatrix}cos(sin^{-1}x)\end{Bmatrix}+cos^{-1}\begin{Bmatrix}sin(cos^{-1}x)\end{Bmatrix}$ $= sin^{-1}\begin{Bmatrix}cos\left(\frac{\pi}{2}-cos^{-1}x\right)\end{Bmatrix} +cos^{-1}\begin{Bmatrix}sin(cos^{-1}x)\end{Bmatrix}$ $= sin^{-1}\begin{Bmatrix}sin (cos^{-1}x)\end{Bmatrix}+cos^{-1} \begin{Bmatrix}sin(cos^{-1}x)\end{Bmatrix}=\frac{\pi}{2}$ |