Practicing Success
In a stream running at 3 km/h, a motorboat goes 12 km upstream and back to the starting point in 60 min. Find the speed of the motor boat in still water. (in km/h) |
$2(2+\sqrt{17})$ $3(2+\sqrt{17})$ $2(4+\sqrt{15})$ $3(4+\sqrt{17})$ |
$3(4+\sqrt{17})$ |
We know that, x = [-b ± √(b2 – 4ac)]/2a We have, In a stream running at 3 km/h, a motorboat goes 12 km upstream and back to the starting point in 60 min Let the speed of boat in still water be x, then According to the question, = 12/(x – 3) + 12/(x + 3) = 1 = 12 [(x + 3 + x – 3)/(x2 – 9)] = 1 = 12 × 2x = x2 – 9 = x2 – 24x – 9 = 0 Compare on ax2 + bx + c = 0 a = 1, b = -24 and c = -9 As we know, = x = [-b ± √(b2 – 4ac)]/2a = x = [24 ± √(242 – 4 × 1 × (-9)]/2 = x = [24 ± √(576 + 36)]/2 = x = [24 ± √612]/2 = x = (24 ± 6√17)/2 = x = 12 ± 3√17 = x = 3 (4 ± √17) Speed of boat in still water = 3 (4 + √17) |