Practicing Success
The integral $∫e^x(tan\, x + log\, sec\, x)dx$ is equal to : |
$e^xlog\, tan\, x+C$ $e^xsec\, x+C$ $e^xlog\, sec\, x+C$ $log\, sec\, x +e^x+C$ |
$e^xlog\, sec\, x+C$ |
$I=∫e^x(\tan\, x + \log\, \sec\, x)dx$ $=∫e^x(f(x)+f'(x))dx$ form here $f(x)= \log\sec x,f'(x)=\tan x$ so $I=e^x\log\sec x+C$ |