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The value of 2 - $\sqrt{\frac{cotθ+cosθ}{cotθ-cosθ}}$ when 0o < θ < 90o is equal to : |
2 + secθ + tanθ 2 - secθ + tan θ 2 - sec θ - tan θ 2 = secθ - tanθ |
2 - sec θ - tan θ |
2 - $\sqrt{\frac{cotθ+cosθ}{cotθ-cosθ}}$ = 2 - $\sqrt{\frac{1+sinθ}{1-sinθ}} × \sqrt{\frac{1+sinθ}{1+sinθ}}$ = 2 - $\sqrt{\frac{(1+sinθ)2}{12-sin2θ}} $ = 2 - $\sqrt{\frac{(1+sinθ)2}{cos2θ}} $ = 2 - secθ - tanθ |
