CUET Preparation Today
A solution of the differential equation $\left(\frac{d y}{d x}\right)^2-x \frac{d y}{d x}+y=0$, is |
$y=2$ $y=2 x$ $y=2 x-4$ $y=2 x^2-4$ |
$y=2 x-4$ |
If, $y=2 x-4$, then $\frac{d y}{d x}=2$ Clearly, these values satisfy the differential equation. |
