Practicing Success
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If $tan^4x - tan^2x= 1$, then the value of $sin^4x + sin^2x$ is : |
$\frac{3}{4}$ $\frac{1}{2}$ 1 $\frac{3}{2}$ |
1 |
$tan^4x - tan^2x= 1$ tan4 x = 1 + tan²x tan4 x = sec²x ( sec²x - tan²x = 1 ) sin4 x = cos²x Now, $sin^4x + sin^2x$ = cos²x + sin²x = 1 ( cos²x + sin²x = 1 ) |
