The side of an equilateral triangle is 36 cm. What is the radius of the circle circumscribing this equilateral triangle?

$12\sqrt{3}$ cm

Calculation

Circum-radius = \(\frac{36}{ √3 }\)

= \(\frac{12 \;×\; 3}{ √3 }\) = 12\(\sqrt { 3}\)

Therefore, the radius of the circle circumscribing this equilateral triangle is 12\(\sqrt {3 }\) cm.