If the base of a right pyramid is trapezium with the length of parallel sides as 12 cm and 15 cm and the distance between them is 8 cm. If the height of the pyramid is 20 cm, find the volume.
Answer & explanation
Correct answer: option 4
Volume of pyramid = \(\frac{1}{3}\) Area of base × height
⇒ volume = \(\frac{1}{3}\) (\(\frac{1}{2}\) (sum of parallel sides) × distance) × height
= \(\frac{1}{3}\) × [\(\frac{1}{2}\) (12 + 15) × 8] × 20
⇒ \(\frac{1}{3}\) × [\(\frac{1}{2}\) × 27 × 8 × 20
⇒ Volume = 720 cm3