If the base of a right pyramid is trapezium with the length of parallel sides as 12 cm and 15 cm and the distance between them is 8 cm. If the height of the pyramid is 20 cm, find the volume.

720 cm³

Volume of pyramid = \(\frac{1}{3}\) Area of base × height

⇒ volume = \(\frac{1}{3}\) (\(\frac{1}{2}\) (sum of parallel sides) × distance) × height

= \(\frac{1}{3}\) × [\(\frac{1}{2}\) (12 + 15) × 8] × 20

⇒ \(\frac{1}{3}\) × [\(\frac{1}{2}\) × 27 × 8 × 20

⇒ Volume = 720 cm³