Which of the following reagent is not used to convert aldehyde into alcohol? |
$H_2/Pd$ $LiAlH_4$ $NaBH_4$ $Sn/HCl$ |
$Sn/HCl$ |
The correct answer is Option (4) → $Sn/HCl$ Conversion of an aldehyde to alcohol is a reduction reaction: R–CHO → R–CH₂OH So we must identify which reagents can reduce aldehydes to primary alcohols. Option Analysis Option 1: H₂/Pd Catalytic hydrogenation using hydrogen gas in presence of palladium reduces aldehydes to primary alcohols. R–CHO + H₂ → R–CH₂OH Hence, this reagent is used for conversion. Option 2: LiAlH₄ Lithium aluminium hydride is a strong reducing agent. It easily reduces aldehydes to primary alcohols by hydride transfer. R–CHO → R–CH₂OH Hence, this reagent is used. Option 3: NaBH₄ Sodium borohydride is a milder reducing agent but is highly effective for reducing aldehydes to alcohols. It selectively reduces carbonyl compounds without affecting many other functional groups. R–CHO → R–CH₂OH Hence, this reagent is also used. Option 4: Sn/HCl Tin in hydrochloric acid is not a reducing agent for aldehydes. It is specifically used for reduction of nitro compounds into amines. Example: Nitrobenzene → Aniline It does not convert aldehydes into alcohols. |