The integrating factor of the differential equation $x\frac{dy}{dx}-y = 2x^2 $ is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{1}{x}$
Dividing given equation by "x"
$\frac{dy}{dx}-\frac{y}{x}=2x$
So $I.F.=e^{\int -\frac{1}{x}dx}=e^{-\log x}=\frac{1}{x}$