A circular wire of diameter 112 cm is cut and bent to form rectangle whose sides are in ratio 5 : 11. The smaller side of the rectangle is?
Answer & explanation
Correct answer: option 4
Diameter = 2r = 112
Circumference of circle = perimeter of rectangle
⇒ 2\(\pi \) r = 2 (l + b)
⇒ \(\frac{22}{7}\) × 112 = 2 (5R + 11R)
⇒ 22 × 16 = 2 × 16R
⇒ 1R = 11
Side of rectangle are = 5 × 11 , 11 × 11 = 55, 121
The smaller side = 55 cm