A circular wire of diameter 112 cm is cut and bent to form rectangle whose sides are in ratio 5 : 11. The smaller side of the rectangle is?

55 cm

Diameter = 2r = 112

Circumference of circle = perimeter of rectangle

⇒ 2\(\pi \) r = 2 (l + b)

⇒ \(\frac{22}{7}\) × 112 = 2 (5R + 11R)

⇒ 22 × 16 = 2 × 16R

⇒ 1R = 11

Side of rectangle are = 5 × 11 , 11 × 11 = 55, 121

The smaller side = 55 cm