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The radii of the ends of a frustum of a cone 7 cm high are 5 cm and 3 cm. Find its volume correct to one decimal place. (Use $\pi=\frac{22}{7}$ ) |
345.6 cm3 359.3 cm3 379.3 cm3 369.3 cm3 |
359.3 cm3 |
Volume of a frustum of cone = \(\frac{π}{3}\)h(R2 + r2 + Rr) = \(\frac{22}{7}\) × \(\frac{7}{3}\) × (52 + 32 + 5 × 3) = \(\frac{22}{7}\) × 49 = 359.3 cm3 |
