If $y=79e^{5x}+85e^{-5x},$ then :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{d^2y}{dx^2}=25y$
$y=79e^{5x}+85e^{-5x}$
$\frac{dy}{dx}=5(79e^{5x}-85e^{-5x})$
$\frac{d^2y}{dx^2}=5×5(79e^{5x}-85e^{-5x})$
$=25(79e^{5x}-85e^{-5x})$
$\frac{d^2y}{dx^2}=25y$