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If $y=79e^{5x}+85e^{-5x},$ then : |
$\frac{d^2y}{dx^2}=79y$ $\frac{d^2y}{dx^2}=10y$ $\frac{d^2y}{dx^2}=5y$ $\frac{d^2y}{dx^2}=25y$ |
$\frac{d^2y}{dx^2}=25y$ |
The correct answer is Option (4) → $\frac{d^2y}{dx^2}=25y$ $y=79e^{5x}+85e^{-5x}$ $\frac{dy}{dx}=5(79e^{5x}-85e^{-5x})$ $\frac{d^2y}{dx^2}=5×5(79e^{5x}-85e^{-5x})$ $=25(79e^{5x}-85e^{-5x})$ $\frac{d^2y}{dx^2}=25y$ |
