ΔPQR is a right angled triangle. ∠Q = 90 degree, PQ = 9 cm and QR = 11 cm. What is the value of cot P ?
Answer & explanation
Correct answer: option 1
ΔPQR is right-angled at Q
PQ = 9 cm and QR = 11 cm
So, cot P = \(\frac{Base}{Perpendicular}\) = \(\frac{9}{11}\)