R is a relation from {11, 12, 13) to {8, 10, 12} defined by y = x - 3. Then $R^{-1}$ is:
Answer & explanation
Correct answer: option 1
R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x - 3 ⇒ x - y = 3
R = {11, 8}, {13, 10}.
Hence $R^{-1}=\{(8,11);(10,13)\}$