Practicing Success
Practicing Success
CUET Preparation Today
The value of the expression $sin[cot^{-1}(cos(tan^{-1}1))]$ is : |
$\sqrt{\frac{2}{3}}$ $\frac{\sqrt{2}}{3}$ $\frac{2}{\sqrt{3}}$ 1 |
$\sqrt{\frac{2}{3}}$ |
The correct answer is Option (1) → $\sqrt{\frac{2}{3}}$ $\sin(\cot^{-1}(\cos(\tan^{-1}1)))=\sin(\cot^{-1}\cos\frac{π}{4})$ $=\sin(\cot^{-1}\frac{1}{\sqrt{2}})$ Using pythagoras triangle
so $\sin(\cot^{-1}\frac{1}{\sqrt{2}})=\sqrt{\frac{2}{3}}$ |
